mrutkows commented on issue #810: wskdeploy assumed "guest" namespace if one is not set URL: https://github.com/apache/incubator-openwhisk-wskdeploy/issues/810#issuecomment-374322281 @rabbah yes, it is in Go client, we make not assumptions in wskdeploy; however, at one point we copied the code from Go client (no longer) and still have a legacy comment that we default to guest (perhaps the "we" is collectively including the known behavior from Go client): grep -rn "guest" . ``` ./wski18n/resources/en_US.all.json:236: "translation": "\nPlease provide a namespace [default value is guest]: " ./deployers/whiskclient_test.go:46: WSKPROPS_NAMESPACE = "guest" ./parsers/manifest_parser.go:248: //The namespace for this package is absent, so we use default guest here. ./parsers/manifest_parser.go:968: * "namespace":"guest", ``` @pritidesai We do need to remove the translated string that indicates we default to guest as well.
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