furqaankhan commented on code in PR #1001:
URL: https://github.com/apache/sedona/pull/1001#discussion_r1316628803
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spark/common/src/main/scala/org/apache/spark/sql/sedona_sql/expressions/InferredExpression.scala:
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@@ -100,6 +100,10 @@ object InferrableType {
new InferrableType[Array[Byte]] {}
implicit val longArrayInstance: InferrableType[Array[java.lang.Long]] =
new InferrableType[Array[java.lang.Long]] {}
+ implicit val intArrayInstance: InferrableType[Array[Int]] =
+ new InferrableType[Array[Int]] {}
+ implicit val javaIntArrayInstance: InferrableType[Array[java.lang.Integer]] =
Review Comment:
No particular reason, scala by default takes `Int`. I guess the same reason
we support `Double` and `java.lang.Double`
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