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https://issues.apache.org/jira/browse/SPARK-17198?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=15434191#comment-15434191
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Dongjoon Hyun commented on SPARK-17198:
---------------------------------------
Hi, [~tuming].
The reported error scenario in HIVE-11312 seems to work without problems in
Spark 2.0 like the following.
{code}
scala> sql("create table orc_test( col1 string, col2 char(10)) stored as orc
tblproperties ('orc.compress'='NONE')")
scala> sql("insert into orc_test values ('val1', '1')")
scala> sql("select * from orc_test where col2='1'").show
+----+----+
|col1|col2|
+----+----+
|val1| 1|
+----+----+
scala> spark.version
res3: String = 2.0.0
{code}
Could you give us some reproducible examples?
> ORC fixed char literal filter does not work
> -------------------------------------------
>
> Key: SPARK-17198
> URL: https://issues.apache.org/jira/browse/SPARK-17198
> Project: Spark
> Issue Type: Bug
> Components: SQL
> Affects Versions: 1.5.1
> Reporter: tuming
>
> I have got wrong result when I run the following query in SparkSQL.
> select * from orc_table where char_col ='5LZS';
> Table orc_table is a ORC format table.
> Column char_col is defined as char(6).
> The hive record reader will return a char(6) string to the spark. And the
> spark has no fixed char type. All fixed char type attributes are converted to
> String by default. Meanwhile the constant literal is parsed to a string
> Literal. So it won't return true forever while doing the equal comparison.
> For instance: '5LZS'=='5LZS '.
> But I can get correct result in Hive using same data and sql string because
> hive append spaces for those constant literal. Please refer to:
> https://issues.apache.org/jira/browse/HIVE-11312
> I found there is no such patch for spark.
>
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