Martin Bode created SPARK-44027:
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Summary: create *permanent* Spark View from DataFrame via PySpark
& Scala DataFrame API
Key: SPARK-44027
URL: https://issues.apache.org/jira/browse/SPARK-44027
Project: Spark
Issue Type: New Feature
Components: PySpark
Affects Versions: 3.4.0
Reporter: Martin Bode
currently only *_temporary_ Spark Views* can be created from a DataFrame:
*
[DataFrame.createGlobalTempView|https://spark.apache.org/docs/latest/api/python/reference/pyspark.sql/api/pyspark.sql.DataFrame.createGlobalTempView.html#pyspark.sql.DataFrame.createGlobalTempView]
*
[DataFrame.createOrReplaceGlobalTempView|https://spark.apache.org/docs/latest/api/python/reference/pyspark.sql/api/pyspark.sql.DataFrame.createOrReplaceGlobalTempView.html#pyspark.sql.DataFrame.createOrReplaceGlobalTempView]
*
[DataFrame.createOrReplaceTempView|https://spark.apache.org/docs/latest/api/python/reference/pyspark.sql/api/pyspark.sql.DataFrame.createOrReplaceTempView.html#pyspark.sql.DataFrame.createOrReplaceTempView]
*
[DataFrame.createTempView|https://spark.apache.org/docs/latest/api/python/reference/pyspark.sql/api/pyspark.sql.DataFrame.createTempView.html#pyspark.sql.DataFrame.createTempView]
When a user needs a _*permanent*_ *Spark View* he has to fall back to Spark SQL
({{{}CREATE VIEW AS SELECT...{}}}).
Sometimes it is easier and more readable to specify the desired logic of the
view through {_}Scala/PySpark DataFrame API{_}.
Therefore, I'd like to suggest to implement a new PySpark method that allows
creating a _*permanent*_ *Spark View* from a DataFrame (e.g.
{{{}DataFrame.createOrReplaceView{}}}).
see also:
[https://community.databricks.com/s/question/0D53f00001PANVgCAP/is-there-a-way-to-create-a-nontemporary-spark-view-with-pyspark]
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