Christophe Bourguignat created SPARK-8535:
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Summary: PySpark : Can't create DataFrame from Pandas dataframe
with no explicit column name
Key: SPARK-8535
URL: https://issues.apache.org/jira/browse/SPARK-8535
Project: Spark
Issue Type: Bug
Components: PySpark
Affects Versions: 1.4.0
Reporter: Christophe Bourguignat
Trying to create a Spark DataFrame from a pandas dataframe with no explicit
column name :
pandasDF = pd.DataFrame([[1, 2], [5, 6]])
sparkDF = sqlContext.createDataFrame(pandasDF)
***********
----> 1 sparkDF = sqlContext.createDataFrame(pandasDF)
/usr/local/Cellar/apache-spark/1.4.0/libexec/python/pyspark/sql/context.pyc in
createDataFrame(self, data, schema, samplingRatio)
344
345 jrdd =
self._jvm.SerDeUtil.toJavaArray(rdd._to_java_object_rdd())
--> 346 df = self._ssql_ctx.applySchemaToPythonRDD(jrdd.rdd(),
schema.json())
347 return DataFrame(df, self)
348
/usr/local/Cellar/apache-spark/1.4.0/libexec/python/lib/py4j-0.8.2.1-src.zip/py4j/java_gateway.py
in __call__(self, *args)
536 answer = self.gateway_client.send_command(command)
537 return_value = get_return_value(answer, self.gateway_client,
--> 538 self.target_id, self.name)
539
540 for temp_arg in temp_args:
/usr/local/Cellar/apache-spark/1.4.0/libexec/python/lib/py4j-0.8.2.1-src.zip/py4j/protocol.py
in get_return_value(answer, gateway_client, target_id, name)
298 raise Py4JJavaError(
299 'An error occurred while calling {0}{1}{2}.\n'.
--> 300 format(target_id, '.', name), value)
301 else:
302 raise Py4JError(
Py4JJavaError: An error occurred while calling o87.applySchemaToPythonRDD.
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