On 06 Mar 2007 03:39:55 -0800, Irin <[EMAIL PROTECTED]> wrote:
>
>   mungkin bisa dicoba seperti berikut ini :
>
> if ((KeyAscii >= vbKey0) and (KeyAscii <= vbKey9)) or (KeyAscii =
> vbKeyBack) or (KeyAscii = Asc("."))
>
>  
>








Terima kasih sdr irin dan lainnya yang telah memberikan solusi dan
alternatif.
Saya memutuskan untuk tetap menggunakan KeyAscii.
(KeyAscii = VbKeyDecimal) tidak fungsi ternyata bisa peke (KeyAscii =
Asc(".")
Sekali lagi terima kasih. :)


[Non-text portions of this message have been removed]



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