Easy but not direct. Get the width that the text would take if placed in a single line with the font size 1 and call it X. Let W be the width of the rectangle and H the height. Let the leading be L and the font size be S.
S = (W * H) / (L * X) If the leading is the same as the font size the equation reduces to: S = SQRT(W * H / X) The actual font size will always be smaller that this because of the word and line breaks but it's a start. You must make several tries until the size fits. Best Regards, Paulo Soares > -----Original Message----- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] On > Behalf Of Youssef Eldakar > Sent: Thursday, July 08, 2004 11:59 AM > To: [EMAIL PROTECTED] > Subject: [iText-questions] Fitting Text in a Rectangle > > Is there an easy way to squeeze or expand text to fit a rectangle? > > Youssef Eldakar > Bibliotheca Alexandrina > Shatby, Alexandria 21526 > Tel: +20-3-4839999 > Fax: +20-3-4879422 > E-mail: [EMAIL PROTECTED] > > NHS^é[){([ZrAÚyj)-Vv~):ÚxUn6ØÖ_uÞÇ^rq^ÆÝb^j!yÞ > +)àhÛØX0ZrHZ&7ØÉXX$Úzb{%lq zm?X( ~zwXb?×Ø > N¬HS^µé[)¢{(ç[ÈZrAÚâyø§‚Äëj)âž -µéÝVœv¸ž~)à±:Úx§€¶¬Uè°›¥Ën6õØŠÖ±é_uçÞÇ¢›^râq©^Æ«¶Éè½éݺbµÈ^²éæj×!yÙÞ +’)àh®ÛŠØ±X¬ŠÜ0ÁZrHZµÊ&‰7±¶«ž²ØžÉŠX§‚X¬¶$ÞÆÚzËb¢{%ŠËl²‹«qç讧zØm¶›?þX¬¶Ë(º· ~ŠàzwþX¬¶ÏåŠËbú?Š×¶«ž²Øž
