Bruno Lowagie (iText) wrote:
>
> In the method you are supposed to implement, you get all
> the necessary coordinates and you can grab the canvas that
> goes under the cells of the table.
>
Wonderful suggestion Bruno! I realized after posting my last reply that I
was stepping backward through the heights array. Now I'm stepping forward
like:
canvas.rectangle(widths[i][0], heights[i + 1],
widths[i][widths[i].length-1]-widths[i][0], heights[i]-heights[i+1]);
And now I have *exactly* what I need. Thanks for your direction!!
Regards,
John
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