How about putting the name of the image in your URL? Or if you
really want something unique - use an MD5 or SHA1 hash.
Leonard
On Jun 22, 2008, at 6:32 AM, Anthony Oganesian wrote:
> Dear All,
>
> I am struggling with a very special requirement and would appreciate
> any
> pointers to a solution. My task requires me to:
>
> 1. Generate a PDF document with several images [original images are
> big, so
> I scale them to fit a particular layout on the page]
> 2. Generated PDF file is viewed in a PDF viewer, which is embedded
> into my
> application. This PDF viewer supports interactive features and allows
> programmatic handling of Link Annotations. When a user clicks on an
> image, I
> have to open the original image in a new window.
>
>
> 1. So, when I generate my PDF, I do the following:
>
> ...
> Image img = Image.getInstance(img_byte_array);
> img.scaleToFit(dimensionX, dimensionY);
> String REFERENCE_ID = F(img)
> img.setAnnotation(new Annotation(0, 0, 0, 0, "img://" +
> REFERENCE_ID));
> ...
>
> The REFERENCE_ID here should be anything that would help me identify
> the img
> when I parse the PDF in step 2,
> so I am looking for any help on creating the F() function
>
>
> 2. In my event handler which is attached to the embedded PDF viewer,
> I do
> the following:
>
> public void handleAnnotactionClick(Annotation annotation)
> {
>
> ...
> String url = annotation.getURI();
> if (url.startsWith("img://"))
> {
> String REFERENCE_ID = url.substring(6);
> // Here I need to scan the PDF and find the original image
> stream,
> // and somehow identify it by the reference key
>
> // 1. I tried scanning using the PdfReader and I am able to
> find the
> PdfStreams with the right subtype,
> // but once I have the stream I can't figure out any way to
> identify the one I need among several
> // 2. I tried using JPedal, but I face the same issue of not
> being
> able to tell one image from another.
> // JPedal is using something it calls an ImageName, but that
> seems to be assigned by JPedal
> }
>
> }
>
> Thank you very much in advance for any help!
> Tony.
>
>
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