No, I guess you will have to intercept the Lua error processing to show
your dialog.
Best,
Scuri
On Mon, Oct 20, 2014 at 4:19 PM, Milind Gupta <[email protected]>
wrote:
> I create a dialog and then to do a task in the background I hide it using
> dlg.visible = "NO". Now the program is executing in the background and once
> it finishes the task function it will return to the function that made it
> invisible and the show it again using dlg.visible = "YES".
> Something Like:
>
> dlg.visible = "NO"
> doTask()
> dlg.visible = "YES"
>
> I have also re-routed print and io.write to output to a text box on the
> dlg itself.
> Now the problem is this: When the program is running in the background
> (doTask function) and it encounters an error which is not caught using
> pcall then it would never reach the dlg.visible = "YES" to make the dialog
> visible but goes back to the IUP Mainloop after writing the error in the
> dialog text box. So now I have no way of accessing the dialog and I have to
> kill the process.
> If I remove dlg.visible="NO" then I see that the error displays the
> message on the text box and then returns to the main loop and then it
> continues.
> So I was wondering if on error the dlg can be made visible
> automatically.
>
> Milind
>
>
>
> On Mon, Oct 20, 2014 at 8:12 AM, Antonio Scuri <[email protected]>
> wrote:
>
>> Hi,
>>
>> What do you mean by "the hidden dialog does not get visible"? Did you
>> called IupShow on the dialog an it didn't work?
>>
>> Best,
>> Scuri
>>
>>
>> On Sun, Oct 19, 2014 at 2:33 AM, Milind Gupta <[email protected]>
>> wrote:
>>
>>> Hi,
>>> I have the following scenario. I have a single dialog which I
>>> hide but I maintain the mainloop to keep the program active and code runs
>>> in the background. But if an error occurs in the code then the hidden
>>> dialog does not get visible. Is it possible to have the dialog become
>>> visible if some error happens in the code?
>>>
>>> Thanks,
>>> Milind
>>>
>>>
>>>
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>>
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>
>
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