Apologies, if you receive this twice - some of my posts seem to
disappear.
> The method getIllegalChildNodeType() can return a legal type. This
> happens if the first node type to come back from getAllNodeTypes() is
> in the fact the type that is not wanted. I must have been unlucky
> here.
>
> A sub-type check is made, but not a type equality check. I adjusted
> the function by adding the following two lines:
>
> public static String getIllegalChildNodeType(NodeTypeManager
> manager,
> String legalType)
> throws RepositoryException {
>
> NodeTypeIterator types = manager.getAllNodeTypes();
> while (types.hasNext()) {
> NodeType type = types.nextNodeType();
> --> if (!type.getName().equals(legalType)) {
> NodeType superTypes[] = type.getSupertypes();
> boolean isSubType = false;
> for (int i = 0; i < superTypes.length; i++) {
> String name = superTypes[i].getName();
> if (name.equals(legalType)) {
> isSubType = true;
> break;
> }
> }
> if (!isSubType) {
> return type.getName();
> }
> --> }
> }
> return null;
> }
>
> I don't believe NodeType.getSupertypes() should return the supertypes
> and itself in which case I think the current function would be fine.
>
> Regards,
> David Caruana
> http://www.alfresco.org
>
>
