Duplicate to https://groups.google.com/g/jackson-user/c/xOGWntrDoRI
Can be removed.
Karsil schrieb am Dienstag, 8. Februar 2022 um 18:30:59 UTC+1:
> Hey everyone,
>
> I'm trying to solve an inheritance problem where a clear deduction is
> currently not possible. A toy example:
>
> // BASECLASS
> @JsonSubTypes( {
> @JsonSubTypes.Type( Child.class )
> } )
> @JsonTypeInfo( use = JsonTypeInfo.Id.DEDUCTION )
> public class BaseModel
> {
> @JsonProperty( value = "baseOne", required = true )
> @JsonPropertyDescription( "some value of base class" )
> protected String m_valueOne = "defaultValue";
>
> @JsonProperty( value = "basTwo", required = true )
> @JsonPropertyDescription( "another value of base class" )
> protected String m_valueTwo;
>
> public BaseModel()
> {
> }
>
> public BaseModel( final String p_value )
> {
> m_valueOne = p_value;
> }
> }
>
> // CHILD CLASS
> @JsonInclude( JsonInclude.Include.NON_NULL )
> public class Child extends BaseModel
> {
> @JsonProperty( value = "childValueFirst", required = true )
> @JsonPropertyDescription( "some value of child class" )
> private String m_child;
>
> public Child()
> {
> }
>
> public Child( final String p_value )
> {
> m_child = p_value;
> }
> }
>
> // TEST
> public class TestDemo
> {
> @Test
> public void testDefault() throws JsonProcessingException
> {
> final List<BaseModel> l_list = Stream.of( new BaseModel(), new Child()
> ).collect( Collectors.toList() );
>
> final ObjectMapper l_mapper = new ObjectMapper();
> final String l_json = l_mapper.writeValueAsString( l_list );
> System.out.println( l_json );
> final List<BaseModel> l_out = l_mapper.readValue( l_json, new
> TypeReference<List<BaseModel>>()
> { } );
> }
> }
>
> Error message (during deserialization):
> com.fasterxml.jackson.databind.exc.InvalidTypeIdException: Could not
> resolve subtype of [simple type, class testproject.demo.BaseModel]: Cannot
> deduce unique subtype of `testproject.demo.BaseModel` (2 candidates match)
>
> The error is quite logical: For the base class, two possibilities can
> actually be deserialized.
>
> I already have encountered the defaultImpl property:
> @JsonTypeInfo( ..., defaultImpl = BaseClass.class )
> But this leads to a high-priority, default behaviour (all child objects
> are deserialized with this default class, which is not intended). I'd
> rather like to give it the lowest priority.
>
> But how actually to solve this? Thanks in advance for any help!
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