> On Mar 28, 2023, at 20:51, Tatu Saloranta <[email protected]> wrote:
>
> But as I said, decoding from bytes to chars itself does not require
> allocations, yet.
> So `parser.getTextCharacters()` for example typically avoids
> allocations (except for buffer boundaries,
> long strings etc).
So would the following work as intended?
public class JsonInterningDeserializer extends JsonDeserializer<String> {
private final CharsToNameCanonicalizer can =
CharsToNameCanonicalizer.createRoot();
@Override
public String deserialize(JsonParser p, DeserializationContext ctxt) throws
IOException, JacksonException {
char[] buf = p.getTextCharacters();
int start = p.getTextOffset();
int len = p.getTextLength();
int hash = can.calcHash(buf, start, len);
return can.findSymbol(buf, start, len, hash);
}
}
Thanks,
Viktor
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