On 04/12/2017 02:16 PM, Ralf Ramsauer wrote:
Hi Vitaly,
On 04/12/2017 07:54 PM, Vitaly Andrianov wrote:
On 04/12/2017 11:11 AM, Jan Kiszka wrote:
Hi Vitaly,
On 2017-04-12 16:57, Vitaly Andrianov wrote:
Hi Jan,
Most of inmate configurations for ARM platform has RAM .virt_start =
0x0. Is that a requirement?
The reset vector is 0x0, so there should be some code at that location
when the inmate wants to start. Can be a fraction of the RAM, though,
just to carry some bootstrap page if you prefer.
A while ago I tried to make an inmate with .virt_start = 0x80000000 and
couldn't load the inmate. I wondering if that is an issue with my
configuration or a Jailhouse limitation. I'm working on porting a AM572x
TI-RTOS based application to run as inmate and for me that is a big
limitation (if that is a real limitation but not my bug). A typical
TI-RTOS application has MMU enabled with identical one-to-one mapping of
the entire DDR (0x80000000-0xffffffff). And the binary entry is
somewhere at the beginning of that range.
I saw couple of linux-demo configuration files with .virt_start != 0x0.
Does jailhouse care the .virt_start != 0x0 in some special way? Or I
just have some issue with my configuration?
In case of Linux, you can see that there is always at least one small
region at virt_start 0 as well. That is were our linux-loader.bin is
put. It does not need identity mapping as it does not do any DMA.
Jan
Hi Jan,
Sorry, I'm confused. From Ralf's reply I understood that I can link my
inmate to not zero address (in my case I use beginning of the DDR -
0x80000000) and set .virt_start to the same address. Also I placed
vector table to the beginning of the image, so the entry point is the
start of the binary. I understood that configuration should work.
Sorry for the confusion, Jan is right, please let me amend:
Currently, relocating inmates is not sufficent, their entry point or
reset vector would have to be changed as well. Jailhouse currently jumps
to guest-phys 0x0.
Ralf
Ralf,
Let's say I have a binary linked to the address 0x80000000 and entry
point 0x8000xxxx. I'll create one page code linked to the 0x0. At the
beginning of that page I have only one instruction:
"b 0x8000xxxx"
I'll concatenate that page and my binary into inmate.bin and create
inmate cell configuration with something like:
.mem_regions = {
/* RAM */ {
.phys_start = phys_memory_reserved_for_inmate
.virt_start = 0,
.size = 0x1000,
.flags = JAILHOUSE_MEM_READ | JAILHOUSE_MEM_WRITE |
JAILHOUSE_MEM_EXECUTE |JAILHOUSE_MEM_LOADABLE,
},
/* RAM */ {
.phys_start = phys_memory_reserved_for_inmate + 0x1000,
.virt_start = 0x80000000,
.size = 0x1000000,
.flags = JAILHOUSE_MEM_READ | JAILHOUSE_MEM_WRITE |
JAILHOUSE_MEM_EXECUTE | JAILHOUSE_MEM_DMA |
JAILHOUSE_MEM_LOADABLE,
},
. . . .
Will it work?
Thanks,
-Vitaly
From your reply I understood that I have to make at least a small
section located at the virt_start = 0x0 address. Is that really necessary?
Thanks,
Vitaly
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