Hi all ( aka Kiste and Rob&Rob ?) :)
One possible solution to take 8 adc average values is below (and does not
work):
const sample_nr = 8 ; buffer size dimension
var word voltage1_a[sample_nr] ; sample array
var word one_ch_ad_read
var word voltage1 = 0 ; the average value we need
const word c256 = 256
var byte i
for 8 using i loop
one_ch_ad_read (0, 0b10, 0b00, 1) ; read adc procedure
ch0_adc_value = c256*ADRESH + ADRESL ; compute result
voltage1_a [i] = ch0_adc_value ; store sample
voltage1 = voltage1 + voltage1_a[i] ; do a sum of all samples each i step
end loop
voltage1 = voltage1 >> 3 ; divide by 8 and get the adc average
The issue is at the line:
voltage1 = voltage1 + voltage1_a[i] ;
initially voltage1 = 0
for i=0 voltage1 = 0 + voltage1_a[0]
for i=1 voltage1 = voltage1 (i=0) + voltage1_a[1] ...etc
this is not working as presumed...
If I remove this line from for...loop...end loop and write as:
voltage1 = voltage1_a [0] + voltage1_a [1] + voltage1_a [2] + voltage1_a [3]
+ voltage1_a [4] + voltage1_a [5] + voltage1_a [6] + voltage1_a
[7]
then everything is ok.
The question is: why it does not work?
thx
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