-----------------------------
Please read the FAQ!
<http://java.apache.org/faq/>
-----------------------------
You can use the JavaMail package to parse the response. It works fairly
well.
-ch
//
// File: FileUploadServlet.java
// Author: Christopher Hoover <[EMAIL PROTECTED]>
// $Id$
//
import java.io.*;
import java.util.*;
import javax.servlet.*;
import javax.servlet.http.*;
import javax.mail.*;
import javax.mail.internet.*;
public class FileUploadServlet extends HttpServlet
{
final static int maximumUploadLength = 10000000;
public void init(ServletConfig config) throws ServletException {
super.init(config);
}
public void doPost(HttpServletRequest request, HttpServletResponse
response)
throws ServletException, IOException
{
if (request.getContentLength() > maximumUploadLength) {
System.err.println("Content too long: " +
request.getContentLength());
response.sendError(response.SC_BAD_REQUEST, "Content too
long.");
return;
}
if
(request.getContentType().toLowerCase().equals("multipart/form-data"))
{
System.err.println("Bad content type: " +
request.getContentType());
response.sendError(response.SC_BAD_REQUEST, "Bad content
type.");
return;
}
try {
Properties props = System.getProperties();
Session session = Session.getDefaultInstance(props, null);
String headers
= "Content-Type: " + request.getContentType() +
"\r\n\r\n";
InputStream messageIS = new SequenceInputStream(new
StringBufferInputStream(headers),
request.getInputStream());
MimeMessage message = new MimeMessage(session, messageIS);
Object content = message.getContent();
if (content instanceof MimeMultipart) {
MimeMultipart mm = (MimeMultipart) content;
int nBodyParts = mm.getCount();
for (int i = 0; i < nBodyParts; i++) {
BodyPart part = mm.getBodyPart(i);
System.out.println("Body part #" + i);
System.out.println("content type :" +
part.getContentType());
System.out.println("description :" +
part.getDescription());
System.out.println("file name :" +
part.getFileName());
System.out.println("size :" +
part.getSize());
System.out.println("line count :" +
part.getLineCount());
}
} else
System.err.println("Content is not MimeMultipart");
} catch (MessagingException e) {
System.err.println("Failed to parse content: " + e);
response.sendError(response.SC_BAD_REQUEST, "Failed to parse
content.");
}
response.setContentType("text/plain");
PrintWriter out = response.getWriter();
out.println("You won big!");
}
}
------
Christopher Hoover
mailto:[EMAIL PROTECTED]
http://www.murgatroid.com
+1-408-348-0304, +1-209-315-6378 fax
> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED]]On Behalf Of Durga Panda
> Sent: Wednesday, September 01, 1999 5:42 AM
> To: [EMAIL PROTECTED]
> Subject: need a sample servlet that process "multipart/form-data"
>
>
> -----------------------------
> Please read the FAQ!
> <http://java.apache.org/faq/>
> -----------------------------
>
> Does anybody have a sample servlet which processes
> "multipart/form-data" or
> any pointer to any site which have this;
> actually I need it for uploadung a file from html using
> <input name="myfile" type="file"> kind of tag;
> Thanks a lot...
>
> ______________________________________________________
> Get Your Private, Free Email at http://www.hotmail.com
>
>
> --
> --------------------------------------------------------------
> Please read the FAQ! <http://java.apache.org/faq/>
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> To unsubscribe: [EMAIL PROTECTED]
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>
--
--------------------------------------------------------------
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