---------------------------------------------------------------- BEFORE YOU POST, search the faq at <http://java.apache.org/faq/> WHEN YOU POST, include all relevant version numbers, log files, and configuration files. Don't make us guess your problem!!! ---------------------------------------------------------------- Probably has something to do with what account the web server is running under. If it is running as a Service (which is how Apache typically runs under NT) and as the Local System account it is not allowed to interact with the desktop unless you check the "Allow service to interact with desktop" checkbox on the Apache service properties page. This won't be a problem if you are starting your own JVM in a debugger. I don't have direct experience with Apache here but that how other services interact with the desktop. -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] On Behalf Of Ilirjan Sent: Friday, February 18, 2000 9:56 PM To: [EMAIL PROTECTED] Subject: Runtime.exec(path\file.exe) does not work with Apache JServ1.1 onNT 4.0 SP 6 ---------------------------------------------------------------- BEFORE YOU POST, search the faq at <http://java.apache.org/faq/> WHEN YOU POST, include all relevant version numbers, log files, and configuration files. Don't make us guess your problem!!! ---------------------------------------------------------------- Environment : WinNT 4.0 SP 6 Apache 1.3.6 JServ 1.1 JDK 1.1.8 JSDK2.0 I have got a servlet which does not work when it calls Runtime.exec(path\file.exe) on above prescribed environment. The point is that the same code works fine with servletrunner. It also works fine if I do the same thing (same environment) but Win98. So it seems the problem stands between WinNT and JServ 1.1 Here is a very small servlet, that someone is very pleased to use to test my problem. import javax.servlet.http.*; import javax.servlet.*; import java.io.*; public class WontWorkOnJServNTServlet extends HttpServlet { String cmd = "d:\\Winnt\\Notepad.exe"; // String cmd = "c:\\Windows\\Notepad.exe"; public void service(HttpServletRequest req, HttpServletResponse resp) throws IOException, ServletException { try { Runtime rr = Runtime.getRuntime(); Process pp = rr.exec(cmd); // Wait for process to exit try { pp.waitFor(); } catch (InterruptedException e) { e.printStackTrace(); } } catch (IOException e) { System.err.println(e); } resp.getWriter().println("Did it work ?"); } } Help will be really appreciated....as I'm completely exhausted. thank you Ilirjan -- -------------------------------------------------------------- Please read the FAQ! <http://java.apache.org/faq/> To subscribe: [EMAIL PROTECTED] To unsubscribe: [EMAIL PROTECTED] Archives and Other: <http://java.apache.org/main/mail.html> Problems?: [EMAIL PROTECTED] -- -------------------------------------------------------------- Please read the FAQ! <http://java.apache.org/faq/> To subscribe: [EMAIL PROTECTED] To unsubscribe: [EMAIL PROTECTED] Archives and Other: <http://java.apache.org/main/mail.html> Problems?: [EMAIL PROTECTED]
