Re: [java ee programming] ParseDouble problem

[Rafał Laczek]

Hi,

Thanks for advice.

Finally I sued

double val = Double.parseDouble(strValue.replace(oldChar, newChar));

In my case it was:

 

double resultDoub = Double.parseDouble(resultStr.replace(",", "."

));

Regards,

Rafal

 

Dnia 16-07-2011 o godz. 18:09 John Masseria napisał(a):

Take a look at NumberFormat:

http://download.oracle.com/javase/1,5.0/docs/api/java/text/NumberFormat.html

public abstract class NumberFormat

extends Format

NumberFormat is the abstract base class for all number formats. This class provides the interface for formatting and parsing numbers. NumberFormat also provides methods for determining which locales have number formats, and what their names are.

NumberFormat helps you to format and parse numbers for any locale. Your code can be completely independent of the locale conventions for decimal points, thousands-separators, or even the particular decimal digits used, or whether the number format is even decimal.

To format a number for the current Locale, use one of the factory class methods:

  myString = NumberFormat.getInstance().format(myNumber);
 

If you are formatting multiple numbers, it is more efficient to get the format and use it multiple times so that the system doesn't have to fetch the information about the local language and country conventions multiple times.

 NumberFormat nf = NumberFormat.getInstance();
 for (int i = 0; i < a.length; ++i) {
     output.println(nf.format(myNumber[i]) + "; ");
 }
 

To format a number for a different Locale, specify it in the call to getInstance.

 NumberFormat nf = NumberFormat.getInstance(Locale.FRENCH);
 

You can also use a NumberFormat to parse numbers:

 myNumber = nf.parse(myString);

2011/7/16 Rafał Laczek <rafal_lac...@wp.pl>

Hi Colleagues,

In my application I have input string field.
String resultStr is parsed into double.
The problem is when resultStr is with "comma" eg. 2,3 instead of 2.3 (with dot).
Can I solve it in any way?
Bellow is my current code.
double resultDoub =Double.parseDouble(resultStr);

Thanks in advance for advice.

Regards,
Rafal



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