Kontorotsui wrote:
>
> aClass extends aSuperClass
> {
> final int v = 1;
>
> aClass()
> {
> super(v);
> }
> }
First off, my understanding of the question is why doesn't v exist when
passed into super. "super" is not a method call like everything else.
It is a special keyword and a way to specify constructor
initialization. What it tells the compiler is to use the contructor
that takes an integer in the aSuperClass. Construction then takes place
from the highest top parent down to the concrete child. In your case,
the type is right, but v does not exist yet until aSuperClass
initializes. The "final" keyword tells the runtime that this value will
not be changed once it is set. So the one person who mentioned using a
"static int v = 1", is probably the way you want to go.
Hope that helps,
Dave
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