Hi folks,
All parameters are ALWAYS passed by value in Java.
When the parameter being passed is an object reference it is the
VALUE OF THE REFERENCE that is passed by value, not the object being
referenced.
This may seem like a moot distinction, but it is not. A method cannot
destroy the reference passed to it by changing the value of the formal
parameter. The formal parameter is a copy.
Regards,
Vartan
[EMAIL PROTECTED] writes:
> On Wed, 13 Oct 1999, Robert Simmons wrote:
>
> > Since everything in java is passed by reference this becomes even more of an
>issue.
> > Therefore can I do the following to achieve the desired safety ?
>
> Well, everything is not passed by reference in Java. I believe primitives
> and immutable types are passed by value. Someone know the exact rules
> behind this? I always have to write a little test program to remember.
> Okay, I'll stop being pedantic.
>
> I think if you do
>
> public void myFunction(final SomeClass var) {
> .. whatever ..
> }
>
> Will do what you desire. Not positive though so some of the other wiser
> folks on the list might wish to confirm this.
>
>
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