Could able to do that using range query String end = "253373251260000";//i.e. 11/30/9999, assume that this is max end date
Term endTerm = new Term("timestamp",end); RangeQuery rangeQuery = new RangeQuery(null,endTerm,true); Sort sort = new Sort("timestamp",true); Filter dupFilter = new DuplicateFilter("id"); Hits hits = searcher.search(rangeQuery,dupFilter,sort); --- On Mon, 11/10/08, Cool The Breezer <[EMAIL PROTECTED]> wrote: > From: Cool The Breezer <[EMAIL PROTECTED]> > Subject: Order the index by timestamp field and Get n documents > To: java-user@lucene.apache.org > Date: Monday, November 10, 2008, 1:21 AM > Hi, > In my index, there is a field called timestamp which is > long value of date. I am trying to get sort all documents > by timestamp and get N documents. > I am trying to find a way to create a query like > "timestamp > 0" and then order the result by > timestamp and get N fields. However I am not able to do > that. Suggest me the best way. Or there are any lowlevel > method available for the same. > > I am using Lucene 2.3.1 and looking into method > search(Weight weight, Filter filter, int nDocs, Sort sort) > in IndexSearcher. Trying to know how to create a Weight > object. > > Anyway, I would really appreciate your suggestion.... > > -RB > > > > > --------------------------------------------------------------------- > To unsubscribe, e-mail: > [EMAIL PROTECTED] > For additional commands, e-mail: > [EMAIL PROTECTED] --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]