Hello Michael,
Thanks for the response,
I have tried the approach suggested by you(TermsEnum) but it is not working for
me. I have used below code.
String field = "address";
try (IndexReader reader = Utils.getIndexReader(indexDirectoryPath))
{
List<LeafReaderContext> leaves = reader.leaves();
for (LeafReaderContext leaf : leaves) {
Terms _terms = leaf.reader().terms(field);
if (_terms == null) {
continue;
}
TermsEnum termsEnum = _terms.iterator();
System.out.println(termsEnum);
}
} catch (IOException e) {
e.printStackTrace();
}
Sent from Mail<https://go.microsoft.com/fwlink/?LinkId=550986> for Windows 10
________________________________
From: Michael Sokolov <[email protected]>
Sent: Friday, November 22, 2019 8:11:25 PM
To: [email protected] <[email protected]>
Subject: Re: Get distinct fields values from lucene index
In Solr and ES this is done with faceting and aggregations,
respectively, based on Lucene's low-level APIs. Have you looked at
TermsEnum? You can use that to get all distinct terms for a segment,
and then it is up to you to coalesce terms across segments ("leaves").
On Thu, Nov 21, 2019 at 1:15 AM Amol Suryawanshi
<[email protected]> wrote:
>
> Hello,
>
> I am using lucene in my organization. I want to know how can I get distinct
> values from lucene index. I have tried “GroupingSearch” API but it doesn’t
> serves the purpose. It will give all documents contains distinct values. I
> have used below code.
>
>
> final GroupingSearch groupingSearch = new GroupingSearch(groupField);
>
> Sort sort = new Sort(new SortField(groupField, SortField.Type.STRING_VAL,
> false));
> groupingSearch.setSortWithinGroup(sort);
> Query query = new MatchAllDocsQuery();
> TopGroups<BytesRef> topGroups = null;
>
> try {
> topGroups = groupingSearch.search(searcher, query, 0, 10);
> } catch (final IOException e) {
> System.out.println("Can't execute group search because of an IOException.
> "+ e);
> }
>
> Sent from Mail<https://go.microsoft.com/fwlink/?LinkId=550986> for Windows 10
>
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