So, I can't have the object in the scene graph if I want to draw it in
immediate mode? Which brings to mind another question... Does immediate
mode rendering use the scene graph at all? If not, how does it know
where to draw the object on the screen? Will it just draw all the
objects on top of each other at the origin? I'm a bit more confused now
than when I started, but such is the learning process....
Thanks for the help.
Andy
On Fri, Apr 21, 2000 at 02:51:47PM +0000, Stephan Kolaroff wrote:
> If I'm not wrong, .draw(Shape3D s) is in fact
> .setAppearance(s.getAppearance). So, I thing you are using its Appearance
> somewhere, somehow, for example in scene graph. Recheck code and Good luck!
>
>
> >From: Andrew Adrian <[EMAIL PROTECTED]>
> >Reply-To: Discussion list for Java 3D API <[EMAIL PROTECTED]>
> >To: [EMAIL PROTECTED]
> >Subject: [JAVA3D] What the heck does this mean????
> >Date: Fri, 21 Apr 2000 08:05:49 -0500
> >
> >I'm getting an odd error when trying to use immediate-mode rendering.
> >
> >"javax.media.j3d.IllegalSharingException: Appearance: Scene Graph
> >appearance may not be in immediate mode"
> >
> >This comes up on a GraphicsContext3D.draw(Shape3D); The Shape3D it's
> >trying to draw is one that I wrote. Basically I have a class that
> >extends Primitive, that based on a constructor argument creates either a
> >Pyramid or a ClosedBox. I wrote both the Pyramid and ClosedBox classes
> >to extend Shape3D, making it really easy (I thought) to do immediate-mode
> >rendering.
> >
> >
> >Can anyone give me a clue on how to fix this, and perhaps why I'm getting
> >it in the first place?
> >
> >Thanks in advance.
> >
> >Andy
> >
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