Excellent suggestion. We use "distance squared" very often because it is a lot faster than doing the square roots to get actual distance.
- John Wright Starfire Research "Simeon H.K. Fitch" wrote: > > > > > What is the best way to get the distance between two points? > > > > ie I want the straight line distance between (0.3, 3, -5) and (6, -3.54, > > 75) > > > > Given two points: P1 = (x1, y1, z1) and P2 = (x2, y2, z2) > > Distance is: > > double d = Math.sqrt(x1*x2 + y1*y2 + z1*z2) > > or I prefer for readability sake: > > import javax.vecmath.*; > > .... > > Point3d p1 = new Point3d(0.3, 3, -5); > Point3d p2 = new POint3d(6, -3.54, 75); > > double d = p1.distance(p2); > > See the comp.graphics.algorithms FAQ for lots solutions to problems such as > this one: > > http://www.faqs.org/faqs/graphics/algorithms-faq/ > > Tip: use squared distance where possible, as computing the square root is > expensive: > > double dSqrd = p1.distanceSquared(p2); > > Simeon > > =========================================================================== > To unsubscribe, send email to [EMAIL PROTECTED] and include in the body > of the message "signoff JAVA3D-INTEREST". For general help, send email to > [EMAIL PROTECTED] and include in the body of the message "help". =========================================================================== To unsubscribe, send email to [EMAIL PROTECTED] and include in the body of the message "signoff JAVA3D-INTEREST". For general help, send email to [EMAIL PROTECTED] and include in the body of the message "help".
