Solve the equation for y in terms of x and z at four corners, then use those 4
coordinate triplets to define a Geometry. If you need the Normal and the
equation describing your plane is:
Ax + By + Cz + D = 0
Then the normal is the vector: (A, B, C)
Is that what you had in mind? An alternative (if you want your plane to look
like a square or rectangle when viewed along the normal) is to start by
building a rectanlge in the x-z plane. Then, to get it oriented right, you
will create a Transform3D for it. The easiest way to do this is to build a
rotation matrix out of an AxisAngle4f. The axis of the axis angle will be the
cross product of the y-axis and either the gradient or the normal. The angle
will be the angle between the y-axis and the normal (just use the Angle()
method in Vector3f).
hope this helps,
john
--
John Brecht
[EMAIL PROTECTED]
http://www.msu.edu/~brechtjo/
Department of Physics and Astronomy
Michigan State University
>
> Can someone suggest me a nice way to draw plane using a three variable equati
on (ex: 2x+3y+z+1=0) using Java 3d API?
> Thanks in advance
> Vasu Suram
>
>
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