Aaron,
Maybe the question and/or answer need to be rewritten to be clearer.
The question meant to ask what would be the minimum bounding sphere you
could use to animate the cube for any position of the cube. For
example,
if you translated the cube such that only .1 meter of one face were
visible, what bounding sphere would animate it.
The answer is supposed to indicate that it is the sphere intersection
with the activation volume of the view that activates the interpolator.
So, in general, you would want a bounding sphere that encloses the
entire visual object.
FOr this example, there is no reason to make the bounding sphere any
larger as this would only animate the cube even when it is not
visible.
To confirm this, you would need to translate the cube such that more
than half is not visible and use a bounding sphere small enough such
that it would not intersect the activation volume.
I hope this helps,
Dennis
> Aaron Finch wrote:
>
> Hi, Just starting this tutorial so I apologize in advance. Question #5
> of the "self test" for chapter one deals with varying the size of the
> bounding sphere. It implies (I think), that the sphere must encompass
> the complete cube for the behavior (rotation of the cube) to be
> active. I guess this means: anything less -> no rotation. But when I
> adjust the sphere to be smaller than the cube it still rotates! I've
> even tried centering the sphere far away from the cube and it still
> rotates. The only time I could get it to NOT rotate was by commenting
> out the 2 lines of code that create the sphere and set the bounds
> (setSchedulingBounds()). Am I missing the whole point?
> Aaron Finch
--
-----
Dennis J Bouvier
[EMAIL PROTECTED]
Find the Java 3D Tutorial "Getting Started with the Java 3D API" at
http://sun.com/desktop/java3d/collateral
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