How does a reference affect it?

On Mon, Dec 6, 2010 at 11:31 PM, Kevin Wright <[email protected]>wrote:

> Liskov means that you can write code which depends on the exact rounding
> behaviour of a float, and it would fail if working with a double.  The types
> are not transparently substitutable.
>
> This isn't a subclasses relationship, nor can it be - given that primitives
> aren't held by reference.
>
> The specification is, quite simply, misleading
> On 6 Dec 2010 23:24, "Miroslav Pokorny" <[email protected]>
> wrote:
> > Liskov principal means a long can stand in for a int and teh caller will
> > work unmodified w/ both. Given some conversion is required between the
> two
> > and the bit patterns are different (eg byte -> double), there is no
> > substitution there is only conversion. One needs different bytecode to do
> > whatever with an int and all the other primitives ignoring boolean and
> other
> > different/weird cases.
> >
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