Miga is correct
To support it see below of time comparisons.
long t1=System.nanoTime();
Integer x=5;
long t2=System.nanoTime();
long diff1=t2-t1;
System.out.println(diff1); // returns 516546
long t3=System.nanoTime();
Integer y=new Integer(5);
long t4=System.nanoTime();
long diff2=t4-t3;
System.out.println(diff2); // returns 4749
hence as Miga said, it is just one operation and hence takes less time.
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