I think the exercise is wrong because it declare average variable as
double type, so the author expected a double type result. If it wasn't
that way, the author must declare: "int average = 0;"
In other hand, if the author declare:
double average = 0;
could compute:
average = (double)(mathGrade+historyGrade+scienceGrade)/3;

Thank you, very much.

--
Adrián


On 19 ene, 00:13, lesh59 <[email protected]> wrote:
> Hi
>
> Strictly speaking, it is wrong to show the result as 73.0 as it is not
> accurate to 1 decimal place.
>
> It would be correct to show the result as 73 if you are not interested
> in the decimal places.
>
> If you are interested in the decimal place then the result should be
> displayed as 73.6 (not 73.0) or 73.66 if you are interested in 2
> decimal places.
>
> Also, the rules of rounding should be specified by the client, the
> exam board in this example may ignore decimal places, but do they
> always round down, round up or to the nearest ?
>
> For this example lets say that the rules say round down, so change the
> average variable to an int, the result will show as 73 (with no
> decimal places).
>
> On Jan 18, 2:48 pm, [email protected] wrote:
>
> > The exercise is not necessarily wrong.
>
> > Displaying someones grade average to decimal places may be wrong,
> > displaying it as a whole number i.e. 73 may be correct, in that case
> > the .66 is meaningless.  So the exercise may be correct
>
> > On 17 Jan, 21:54, Adrián E. Córdoba <[email protected]> wrote:
>
> > > I understood.
> > > So, that exercise is wrong: the type of variables isn't correctly
> > > used.
> > > Thank you, so much.
>
> > > On 17 ene, 04:58, Steffani Trinitra Setyasari <[email protected]>
> > > wrote:
>
> > > > Maybe I can help you to explain what happened....
> > > > The type of variables  "mathGrade", "historyGrade" and 
> > > > "scienceGrade" is integer. The divider of "average" is "3" that its 
> > > > type is integer,too. Both the numerator and denominator are integer so 
> > > > the result will be integer too. Although the result of "average " is 
> > > > 73.66.., it will be rounded off to 73. But because the type 
> > > > of "average" is "double" so the result is 73.0
> > > >  
> > > > If you want to get the exact result of "average" maybe you can change 
> > > > the divider "3" to "3.0" or change the type of "mathGrade", 
> > > > "historyGrade","scienceGrade" to double.
> > > >  
> > > > Cheers!
>
> > > > --- On Sat, 17/1/09, Adrián E. Córdoba <[email protected]> wrote:
>
> > > > From: Adrián E. Córdoba <[email protected]>
> > > > Subject: [java programming] Wrong average in LAB-1034
> > > > To: "Free Java Programming Online Training Course By Sang Shin" 
> > > > <[email protected]>
> > > > Date: Saturday, 17 January, 2009, 2:38 AM
>
> > > > I think something is wrong in LAB-1034, Exercise 1 if/else control
> > > > structure, "(1.1) Build and run a Java program that uses if/else
> > > > control structure".
> > > > If you follow the directives in that LAB, and build an run
> > > > MyGradesProject and enter the math, history, and science grades (78,
> > > > 56 and 87 respectively) like the figures show, the program compute and
> > > > display that the average is "73.0" as Figure-1.15 shows.
> > > > But, if you compute the same average:
>
> > > >                                 (78+56+87) / 3
>
> > > >  in a calculator (like Windows Calculator), the average is "73.66..".
> > > > What's wrong?
>
> > > > Thank you in advance.
>
> > > >       Importing contacts has never been easier. Bring your friends over 
> > > > to Yahoo! Mail today!http://www.trueswitch.com/yahoo-sg-Hide quoted 
> > > > text -
>
> > - Show quoted text -
>
>

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