On Jun 28, 11:34 am, miga <[email protected]> wrote:
> On Jun 28, 7:41 pm, Gibbs <[email protected]> wrote:
>
> > On Jun 27, 8:39 pm, miga <[email protected]> wrote:
>
> > > On Jun 27, 10:45 pm, Dan <[email protected]> wrote:
>
> > > > while (i<names.length)
> > > > {i++;
>
> > > Move the line above
>
> > > > if (names[i].equals(searchName)){
> > > > foundName = true;
> > > > break;
> > > > }
> > > just here
> > > > }
>
> > OK--I finished this lesson last night, and initially had the i++
> > directly below the "break" (Inside the following }). I realized this
> > wouldn't work,
> > and then placed it correctly, but I still haven't entirely wrapped my
> > mind
> > around it. Am I misunderstanding exactly what "break;" does? Also,
> > am I
> > correct in that the i++ is still falling under the while condition in
> > this
> > placement? Not sure if I'm making myself clear, but any help would be
> > appreciated.
>
> The correct code is:
>
> int i = 0;
> while (i < names.length) {
> if (names[i].equals(searchName)) {
> foundName = true;
> break;
> }
> i++;
> }
>
> So, first you initialize the counter before the while in order to
> have a counter, as contrary to a for loop there is no automatic
> counter initialization inside a while loop.
> Then you traverse the array of names by the indexes. Any array begins
> with an index of 0 and terminates with an index of n-1 if n is the
> size of the array.
> Hence your while loop goes from 0 included to names.length excluded
> (that's exactly how it is defined inside the while (...) line.
> Then once you get at a particular index you inspect whether or not the
> particular name corresponding to this index equals the given name (the
> one given by the JOptionPane above the while loop.
> If it equals it, you put a predefined flag to true - to be able to
> test it once you will be outside of the while loop - and you go out of
> the loop - since you have found a match hence your job is done with
> the search.
> If not, you are not done with the search so you must get at the next
> name in the array, to do it, you just increment i and as it is the
> last line of the while loop it goes automatically to the first line to
> test whether or not you are past the end of the array, if not it does
> again the search for the given name as above, if it is it goes out of
> the loop automatically.
> So that, in the end, as you define before the while loop the flag to
> false, if you have found a match inside the loop, you've got a true,
> if not you've got a false.
> Hope it is clear now. Just a matter of thinking how you will
> dichotomize it manually with your brain - if I dare say so -, and then
> transcript it in Java.
Awesome! Somehow, I was missing that the break, when the true
was found, took you out of the entire loop and not just
the particular command. Duh! Makes perfect sense now. Thanks!
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