On Aug 14, 8:11 am, siva prasad <[email protected]> wrote:
> 1. public class TestOR {
> 2. public static void main( String[] args ){
> 3. int i = 0;
> 4. int j = 10;
> 5. boolean test= false;
> 6. //demonstrate ||
> 7. System.out.println(j++);//10
> 8. test = (i < 10) | (j++ > 9);//11
> 9. System.out.println(i);
> 10. System.out.println(j++);//12
> 11. System.out.println(j++);//13
> 12. System.out.println(test);
> 13. //demonstrate |
> 14. test = (i < 10) || (j++ > 9);//14
> 15. System.out.println(i);
> 16. //System.out.println(j);//1
> 17. System.out.println(j);//14
> 18. System.out.println(j++);//14
> 19. System.out.println(test);
> 20. }
> 21. }
>
> O/p:
>
> 10
> 0
> 12
> 13
> true
> 0
> 14
> 14
> true
>
> I couldnt understand y the value of j didnt change in the lines 17 & 18 of
> the above program.
The operator ++ when using after the variable (aka j++) is applied
after the method when it is used. That is in:
System.out.println(j++); it first display the current value of j, then
increment the value of j.
Use ++j if you want to increment first and then use the newly
incremented value in the method where you call it:
System.out.println(++j);
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