Hello All,
This is my opinion.
When the user enters an integer then hits "Enter". Two things have just been
entered: the integer and a "newline" which is "\n".
The method you are calling "netxtIn()" , it only reads in a integer, and
then push a "newline" into next input stream.
You can use this code:
If(in.hasNextInt()){
myInt=in.nextInt();
}else{
If(in.hasNext()){
myStr=in.next;
}
From: javaprogrammingwithpassion@googlegroups.com
[mailto:javaprogrammingwithpass...@googlegroups.com] On Behalf Of Olukosi,
Olanrewaju Temitope
Sent: Tuesday, November 16, 2010 1:42 AM
To: javaprogrammingwithpassion@googlegroups.com
Subject: [java programming] Java Error using Scanner(System.in)
Hello All,
I really need your help here. I tried running this code but was having
problem with the Scanner method. When it gets to the second input, it skips
to the third one. I mean when it gets to tName, it only prints the
System.out.print statement and then prints the next statement without giving
the prompt input for the former statement. Kindly help check what I am
getting wrong.
Help guys.
import java.util.Scanner;
public class MineClass {
private static int tNum, tMM, noQ;
private static String tName, tFName, tIMode;
private static double [] quizMark;
/*
* This method reads in all the values that will be needed for the program.
*/
public static void main(String[] args){
Scanner in = new Scanner(System.in);
System.out.print("TNNo: ");
tNum = in.nextInt();
System.out.println("LFN: ");
tName = in.nextLine();
System.out.println("TFN: ");
tFName = in.nextLine();
System.out.print("IMM: ");
tIMode = in.nextLine();
System.out.print("What To Cal?: ");
noQ = in.nextInt();
quizMark = new double [noQ];
for (int a=0; a<noQ; a++){
System.out.print("The House No " + (a+1) +": ");
quizMark[a] = in.nextDouble();
}
System.out.println("Calsk: ");
tMM = in.nextInt();
}
}
Regards
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Thank you -- Tope Olukosi
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