Hi Michel
The statements :
-- SomeType[ ] ages = null;
declares a variables to be used as an array of objects of SomeType.
-- ages = new SomeType[ 3 ];
creates a three elements array (each element is empty:
System.out.println(ages[i]) will print "null").
-- for ( int i = 0 ; i < ages.length ; i++ ) ages[i] = new SomeType();
stores in each element of the array an object of SomeType
Imagine now that SomeType is int[ ]
Then:
-- int[ ][ ] ages = new int[3][ ];
declares a variable to be used as an array of three elements,
each element will be an array of int,
each element is for the moment null
-- for ( int i = 0 ; i < ages.length ; i++ ) ages[i] = new int[4];
associates to each element of the array "ages" an array of four
integers.
The same thing can be written as:
-- int[ ][ ] ages = new int[3][4];
Now:
-- ages is an array of three elements, each element being an array of
four integers
-- ages is an array of arrays
-- ages[2] is an array of integers
-- ages[2][1] is an integer
-- for ( int i = 0 ; i < ages.length ; i++ ){ // for each of the 3
arrays in ages
for ( int j = 0 ; i < ages[i].length ; j++ ) { // for each of
the 4 integers in the i-th array
ages[ i ][ j ] = i * j; // The j-th integer in the i-th
array set to i * j
}
}
Hope it helps
Mihai
Le 12/02/2011 15:34, Michel a écrit :
Hello folks,
Can someone please help me understand this part of the code from
LAB-1036: Exercise 1, part 2?
// Display the value of each entry in the array
for( int i=0; i<ages.length; i++ ){
System.out.println("\nStarting row " + i);
for( int j=0; j<ages[i].length; j++ ){
ages[i][j] = i * j;
System.out.print( ages[i][j] + " " );
When we say ages[i][j] = i * j; does that mean that if for instance
i=2 and j=2 then the array will display as number 4 (2*2=4)? I guess
what I don't understand is how an array that is represented as rows
and columns can equal a number (since i * j is a number)?
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