Here is a very simple test case.
//b
I would expect b1, b2, b3, b4, b5, b6
All the other programs I have tried return that, Jaxen returns
B1, b4, b2, b3, b5, b6
<?xml version="1.0" encoding="UTF-8"?>
<a>
<a>
<b id='b1'></b>
<a>
<b id='b2'></b>
<b id='b3'></b>
</a>
</a>
<a>
<b id='b4'></b>
<a>
<b id='b5'></b>
<b id='b6'></b>
</a>
</a>
</a>
-----Original Message-----
From: James Strachan [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, March 19, 2002 10:24 AM
To: Mark Hortman; [EMAIL PROTECTED]
Subject: Re: [Jaxen] How to use position() function
From: "Mark Hortman" <[EMAIL PROTECTED]>
> Can someone help a xpath newbie figure out a simple xpath expression?
>
> Upon learning that //someelement does not guarantee the order that things
> come back in are document order, I have switched tacts and decided to try
to
> handle it my self. I was thinking about playing around with the
position()
> function, but cannot get Jaxen to return the position of an element to me.
Though generally //someelement will return things in order. Jaxen should
walk the document tree in order matching XPath expressions so for simple
paths like //foo it should work. Or do you have a test case where it
doesn't?
James
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