I thought it had to be a lower case r as in jrf *-r* FILENAME

Richard Kann
Comp-Ware

On 5/25/2012 2:06 PM, David Grenfell wrote:


Yep, you're right
Dave
------------------------------------------------------------------------
Date: Fri, 25 May 2012 19:01:34 +0100
From: [email protected]
To: [email protected]
Subject: Re: jbase question or two

Try "jrf -R FILENAME"   .. The order seems to matter...

Regards
Simon

On 25/05/2012 18:57, David Grenfell wrote:

    Thank-you Simon.   I just checked my  file, and from just
    eye-balling it, I figure about 250 bytes per item, so I can lower
    my size by about 75%.

    I tried the "jrf FILENAME -R" but didn't get any report.  Using
    vers. 4.3.10 on xp-pro  I was in the folder where the file exists.

    Dave.

    ------------------------------------------------------------------------
    Date: Fri, 25 May 2012 17:51:27 +0100
    From: [email protected] <mailto:[email protected]>
    To: [email protected] <mailto:[email protected]>
    Subject: Re: jbase question or two

    See inline below

    On 25/05/2012 17:42, David Grenfell wrote:

        Good Day to you all:

        I am about to set up a new account and have a couple of
        questions regarding file sizing.

        1/  Is there a dict item I can use to see the size of my items
        in a file ?  For example.... "LIST FILENAME size"  which would
        show me the item ID and the size of the item.

    LIST FILENAME *A9999     will work.

        2/Once I have a look at the items sizes, I assume I can do the
        following to create a file with the approximate size.

        For now, lets assume that there are 1000 bytes per item.  Each
        bucket holds 4096 bytes, so approximately 5 items per bucket.

        67000 items/5 indicates 13200 buckets

        so.... CREATE-FILE FILENAME 3 13200  should do it.

        Am I correct ? or is 13200 too much?

    It sounds reasonable.   Fill it with data and then use jrf
    FILENAME   to resize it.

        Dave.
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