> more practical solution is to compute the acceleration (i.e., the second > derivative of the Tension). The peak is where acceleration is near 0. The > calculation would be an O(1) operation, as the only thing that would be > involved is differencing the EMAs. thanks for the reply! any hint on how to do differencing the EMAs? I am so sad that I am no math genius :-(
-- You received this message because you are subscribed to the Google Groups "JBookTrader" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/jbooktrader?hl=en.
