Dear All;
I need to upload one excel file to server and then to parse it to
get it's contents. In JSP file i have following code:
| <form method="post" enctype="multipart/form-data"
action="<portlet:actionURL/>">
| File: <input type="file" name="file" size="25">
| <input class="boldFlatbtn" type="submit" name="Upload_File" value="Upload
File"/>
|
| </form>
|
In processAction i am using following code:
System.out.println("Uploaded file path is : " +
actionRequest.getParameter("file"));
This is not showing me the file name.
Please help me to how i can get that uploded file at processAction and to save
it.
I googled to find answer but i could not find any good results.
Thanks in advance;
Vikash Anand.
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