Thats exactly what I want to do (just a query) I guess I dont have a good
understanding of EJBs yet(or Java in general) this is not a good induction
into java programing!!
So I need to execute a query in a JSP or Jbean to fill my <option> box?!
THANKS!
-----Original Message-----
From: David Jencks [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, September 26, 2001 1:51 PM
To: [EMAIL PROTECTED]
Subject: Re: [JBoss-user] Custom finders in Jaws
ummmm
if you only want the last name ... you need an entity bean with only the
last name in it?? You will have big problems if 2 people have the last
name, usually last name is not a very good candidate key.
I think maybe what you want to do here is not get a collection of entity
beans, but to just execute a query in a session bean and get all
(distinct?) last names (do you want an id too??) and put them as strings in
a list of some kind.
Finders get you a collection of entity beans, normally entity beans do not
have lazy loading of fields/columns... you might be able to do this with
ejb 2.0, but even there I doubt it is what you want.
david jencks
On 2001.09.26 14:04:50 -0400 [EMAIL PROTECTED] wrote:
> Howdy, How can I declare a findByLName() in jaws, I tried this.Like the
> docs
> chpt 6
> <entity>
> <ejb-name>ClassBean</ejb-name>
> ...
> <finder>
> <name>findByLName</name>
> <query>LNAME!=null</query>
> //What I want is for the collection to contain all lastNames from all
> records(I guess I need a wildcard here so It will return all)
> //Similar to a findAll() except returning only 1 column from the table.
> </finder> </entity>
> THANKS!!!
> Graham
>
>
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>
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