Looking for LiteralFactory.createLiteral(String v, String language) equivalent.

[Dick Murray]

Hello all.

I'm looking for a LiteralFactory.createLiteral(String v, String 
language) equivalent. I know Model has a createLiteral(String v, String 
language) but I don't have a Model at the point I need to create the 
Literal. I've followed the Model createLiteral but either got lost or 
confused or both!

In context I have the following method which creates a Statement based 
on some parameters and uses ResourceFactory to create?.

    public Statement getStatement(VelocityContext context) {
        Resource subject = 
ResourceFactory.createResource(evaluate(context, getSubjectURI()));

        Property property = 
ResourceFactory.createProperty(evaluate(context, getPropertyURI()));

        Resource objectType = 
ResourceFactory.createResource(evaluate(context, getObjectType()));

        if (objectType.equals(RDFS.Resource)) {
            return ResourceFactory.createStatement(subject, property, 
ResourceFactory.createResource(evaluate(context, getObjectValue())));
        }

        if (objectType.equals(RDFS.Literal)) {
            if (hasObjectDatatype()) {
                return ResourceFactory.createStatement(subject, 
property, ResourceFactory.createTypedLiteral(evaluate(context, 
getObjectValue()), 
TypeMapper.getInstance().getTypeByName(evaluate(context, 
getObjectDatatype()))));
            } else {
                if (hasLanguage()) {
                    return ResourceFactory.createStatement(subject, 
property, NEED_TO_CREATE_A_LITERAL_WITH_LANGUAGE);
                } else {
                    return ResourceFactory.createStatement(subject, 
property, ResourceFactory.createPlainLiteral(evaluate(context, 
getObjectValue())));
                }
            }
        }

        throw new Exception(String.format("Unknown objectType [%s].", 
objectType));
    }