Whoops, this is the code:
def parTask = [:]
for(int i = 0; i < all_nodes.size(); i++) {
def node_name = all_nodes[i]
parTask[node_name] = {
node(node_name) {/* stuff to do in parallel across selected nodes */ }
}
}
parallel parTask
On Monday, July 13, 2015 at 5:19:57 PM UTC-7, Anshu Arya wrote:
>
> The workaround right now is to just use normal C-style loops. For example
> if you want to do stuff in parallel:
>
> def parTask = [:]
>
> for(int i = 0; i < all_nodes.size(); i++) {
>
> def node_name = all_nodes[i]
> parTask[node_name] = { /* stuff to do in parallel */ }
>
> }
> parallel parTask
>
>
> On Monday, July 13, 2015 at 5:02:01 PM UTC-7, Owen B. Mehegan wrote:
>>
>> I'm trying to accomplish basically the same thing - I have identical
>> steps that I want to run on >1 slave, in parallel. Is there any other
>> succinct way to write this? Right now I am duplicating everything for each
>> slave, which should offend anyone's sense of programming decency :)
>>
>> Being able to write:
>> node('linux_slave', 'windows_slave') {
>> // some steps to run in parallel on both slaves
>> }
>>
>> would be fantastic.
>>
>> On Tuesday, June 16, 2015 at 12:38:13 PM UTC-7, Jesse Glick wrote:
>>>
>>> On Monday, April 27, 2015 at 11:18:09 PM UTC-4, Anshu Arya wrote:
>>>>
>>>> java.io.NotSerializableException: java.util.AbstractList$Itr
>>>>
>>>
>>> JENKINS-27421 <https://issues.jenkins-ci.org/browse/JENKINS-27421>
>>>
>>
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