Yes, I am using Multibranch pipeline.
I already have the branch name with env.BRANCH_NAME, but only some 
designated branches have a list of slave nodes.
If the branch is master, it should build on all slave nodes in the 
environment for master.
If the branch is userName/work which is branched out from master it should 
also build in the environment for master.
I am using the parameter buildEnvironment in the Jenkinsfile to determine 
which environment of slave nodes to build on.

Environment: master
Nodes: master-sles12-x86_64, master-centos7-x86_64 ...


tirsdag 2. august 2016 12.01.10 UTC+2 skrev Alan Clucas følgende:
>
> How are you building all these branches? If you're using a multibranch 
> pipeline (or anything else where the branch name is part of the job name) 
> then env.JOB_NAME contains a string you can mangle to extract the branch 
> details.
>
> On Tuesday, 2 August 2016 07:19:22 UTC+1, Sverre Moe wrote:
>>
>> I am using the variable buildEnvironment to determine which set of nodes 
>> the branch should be built on.
>> Each release branch (including git master) has their own list of slave 
>> nodes.
>>
>> Jenkinsfile:
>> #!groovy
>>
>> def buildEnvironment = "master"
>> def param2 = null
>> String[] args = [buildEnvironment, param2] as String[]
>>
>> def build = new com.company.ci.Build()
>> build.execute(args)
>>
>> There has been some concerns that the Jenkinsfile could cause forever 
>> merge conflicts because one parameter is different among different branches.
>> origin/master -> def buildEnvironment = "master"
>> origin/releaseA -> def buildEnvironment = "releaseA"
>>
>> I could use the branch name to determine which buildEnvironment to use, 
>> but that would not work when it is a feature or work branch created from 
>> either master or a release branch. The branch name master would work for 
>> branch master, but not myUser/work that is branched out of master.
>>
>> Anyone have any idea how this can be solved without keeping the parameter 
>> buildEnvironment in the Jenkinsfile?
>>
>

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