Baptiste Mathus:

> Backslash escape is because the parser needs to know you're not
> trying to "despecialize" the following character. By default \
> *is* a special character. (E.g. "\to" would mean \t, which is a
> tabulation, then the letter o).
> So using \ because the second \, the parser just
> 
> It's the same in Java, C AFAIR and probably most languages BTW.

I know about the purpose of escape characters, but -- until
Gianluca's reply -- I didn't know where to look for their exact
specification in the declarative syntax.

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