Have tried using the CallLambda Userfunction class from
http://herzberg.ca.sandia.gov/jesswiki/view?LambdaCallUserFunction
(load-function CallLambda)
(deftemplate functional-fact
(slot func)
)
(bind ?f (lambda (?x) (> 1 ?x)))
(assert (functional-fact (func ?f)))
(defrule test-me
(functional-fact (func ?f))
(test (lcall ?f 0))
=>
(printout t "1 > 0" crlf))
fails with:
Jess reported an error in routine lcall
while executing (lcall ?f 0)
while executing 'test' CE
while executing rule LHS (TECT).
Message: first argument is not a lambda definition. 4096.
Program text: ( defrule test-me ( functional-fact ( func ?f ) )
( test ( lcall ?f 0 ) ) = > ( printout t "1 > 0" crlf ) ) at line 17.
Seems as though nothing I can do with the slot value will turn it into
a function call.
On Aug 14, 2008, at 8:23 AM, Hal Hildebrand wrote:
I would like to have functions contained in the slot value of a fact
and then apply them. I can create and assign the function values by
using (lambda ...), which seems to be what I'm looking for on that
side of the equation:
(deftemplate functional-fact
(slot func)
)
(assert (functional-fact (func (lambda (?x) (> 1 ?x)))))
However, the question becomes how do I actually call this function?
What I would like to do is use these in test CE:
(deftemplate functional-fact
(slot func)
)
(assert (functional-fact (func (lambda (?x) (> 1 ?x)))))
(defrule test-me
(functional-fact (func ?function))
(test (?function 0))
=>
(printout t "1 > 0" crlf))
However, this does not work as I would expect instead failing with:
Jess reported an error in routine call
while executing (call ?function 0)
while executing 'test' CE
while executing rule LHS (TECT).
Message: No method named '0' found in class jess.Deffunction.
Program text: ( defrule test-me ( functional-fact ( func ?
function ) ) ( test ( ?function 0 ) ) = > ( printout t "1 > 0"
crlf ) ) at line 11.
Clearly, I'm not understanding this and would appreciate any help
from those on the list.
Thanks.
