Hi Buben�k,

I run Jetspeed as a service by running Tomcat as a service. This is what I use.

tomcat  -install "Apache Tomcat" "E:\jdk\jre\bin\server\jvm.dll"
        -Xmx64m -Xm64m
        -Djava.class.path="E:\tomcat\bin\bootstrap.jar"
        -Dcatalina.home="E:\tomcat"
        -start org.apache.catalina.startup.BootstrapService -params start
        -stop org.apache.catalina.startup.BootstrapService  -params stop
        -out "E:\tomcat\logs\stdout.log"
        -err "E:\tomcat\logs\stderr.log"

the only significant difference I can see is that I use absolute paths and you use relative paths. Try with absoulte paths.


I use Tomcat 4.1.24, Jetspeed 1.4b4, JDK 1.4.2 beta



Roshan




From: Buben�k Miroslav <[EMAIL PROTECTED]>
Reply-To: "Jetspeed Users List" <[EMAIL PROTECTED]>
To: "Jetspeed (E-mail)" <[EMAIL PROTECTED]>
Subject: Jetspeed as win service
Date: Wed, 25 Jun 2003 11:14:46 +0200

Hi,
does anybody know, hot to run tomcat with jetspeed as win service?

I've tried to use tomcat.exe -install jetspeed ...
Servise is succesfully installed, but when I want to start this service, it appears warning windows with massage, that "Windows cannot start this service. The service did not return an error. This could be an internal WIndows error or an interval service error. ..."


My command line is:
..\bin\tomcat.exe -install jetspeed C:\Java\j2sdk1.4.1\jre\bin\server\jvm.dll -Djava.endorsed.dirs="..\bin;..\common\endorsed" -classpath "C:\Java\j2sdk1.4.1\lib\tools.jar;..\bin\bootstrap.jar" -Dcatalina.base=".." -Dcatalina.home=".." -Djava.io.tmpdir="..\temp" -start org.apache.catalina.startup.Bootstrap -params start -stop org.apache.catalina.startup.Bootstrap -params stop -out ..\logs\stdout-service.log -err ..\logs\stderr-service.log -current ..\service


I use Tomcat 4.1.12, Jetspeed 1.4b4, w2k pro SP3, JDK 1.4.1

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