On 25/02/2010, Rodolfo Landa <[email protected]> wrote: > Hi all, > > I have a test plan that runs 1 user, 1 loop. It has 4 HTTP Requests. I get > the throughput with the Graph Results (1,666.667/minute) and with the > Aggregate Report (27.8/sec). > > 27.8 * 60 = 1668/min (That's close enough to 1666.667 for me) > > I am writing the results in a CSV file because I want to know how I can > manually get the same results: either 27.8/sec or 1666.667/minute. These are > the results: > > TimeStamp Elapsed Response Code Bytes Latency > 1267118622422 106 500 505 106 > 1267118622534 12 200 412 12 > 1267118622550 8 202 399 7 > 1267118622561 5 200 0 5 > > > Given the above data, how can I get 27.8 or 1666.667?
Throughput = samples/elapsed. = (4 samples * 1000 ms in a second) / (1267118622561 + 5 - 1267118622422) = 4000 / 144 = 27.777777777777... > I am looking at the right place (I defined the csv file in the Filename > field from the Aggregate Report)? > > Regards, > > > Rodolfo > --------------------------------------------------------------------- To unsubscribe, e-mail: [email protected] For additional commands, e-mail: [email protected]
