> [getting list mail but still not able to reply on-list]
>
> On [2005-Jul-28]  Miguel <[EMAIL PROTECTED]> wrote:
>> I am not exactly sure what is going on ... but here is my theory ...
>>
>> One channel is red
>>
>> The other channel is cyan ... green + blue ... I observe that the the
>> byte values for G and B are always exactly the same.
>>
>> I guess that they are building the left and right images independently
>> as
>> grey scale, then extracting the R from one image and the G+B from the
>> other.
>
> I think "imposing" rather than "extracting". When I get back in the office
> I can send an image with almost a complete separation between two spheres
> and showing the colour content.

Where you sit depends upon where you stand :-)

For each pixel I will have two RGB values, left and right. I need to
combine them to form one RGB value.

>> I need to think about how to implement this ...
>
> I think you just need to calculate the two images
> (either via rotation or by the asymmetric frustrum)

I am still using rotation ... have not implemented asymmetric frustrum.

> and then impose the colour value + intensity value (lightness)
> corresponding to the base greyscale pixel in that image.

Each 'greyscale pixel' will be an RGB value.

But, since they are 'greyscale' the component bytes R, G and B will
actually be equal. This means that we can think of left and right as byte
values in the range 0-255, not RGB values.

The final result is composed of the R byte from the left and the G+B bytes
from the right (or vice versa)

If you want red/blue instead of red/cyan then leave the green component
set to 0.


Miguel

-----
Open Source Molecular Visualization
www.jmol.org
[EMAIL PROTECTED]
-----



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