This is always a royal pain to get right. Certainly looks like a rotation matrix to me. It's got the right form. My guess is you put the vector on the right and multiply as:
x' = m11*x + m12*y + m13*z across the top row of that matrix. Likewise for y' across the second. Does that not work? Bob Timothy Driscoll wrote: >hi, > >I have two structures that I have aligned using a program called >MUSTANG. the program gives me a 3x3 transformation matrix like this >one: > > 0.58 0.805 0.125 > 0.521 -0.484 0.703 > 0.626 -0.342 -0.7 > > >in order to superimpose my second structure onto the coordinate >system of the first, I am told that I should apply this matrix to the >xyz coords of the second. I thought this could be done via a simple >matrix multiplication, but apparently not. > >can anyone please suggest a reference that deals with this? > > > >thank you, > >tim > > ------------------------------------------------------------------------- This SF.net email is sponsored by DB2 Express Download DB2 Express C - the FREE version of DB2 express and take control of your XML. No limits. Just data. Click to get it now. http://sourceforge.net/powerbar/db2/ _______________________________________________ Jmol-users mailing list Jmol-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/jmol-users
