Rolf Huehne wrote:
>The first thing I noticed was that I had to provide the whole loop
>commands in a single line. Distributing it over several lines as in the
>example provided in the documentation resulted in the following error
>message:
>
> script compiler ERROR: missing END for for
>
>My script commands first initialize the echo and then run the countdown:
>
> set echo myecho 1% 99%; ~cd="Start"; echo %{~cd};
> for ( var i=5; i>0; i = i - 1); ~cd=i; delay 1; end for; ~cd="";
>
>The loop never got beyond displaying "5" and I had to type "quit" in
>order to be able to run additional commands.
>
>
>
The following both work OK in Jmol 11.3.25:
for ( var i=5; i>0; i = i - 1); ~cd=i; delay 1; echo @i; end for; ~cd="";
for ( var i=5; i>0; i = i - 1)
~cd=i
delay 1
echo @i
end for
~cd=""
Of course, without the echo, it just sits there for 5 seconds looping.
Maybe that's the problem?
>If I used a "while" loop instead it worked as expected:
>
> i=5; while (i>0); ~cd=i; delay 1; i = i - 1; end while; ~cd="";
>
>
>While testing this I noticed that the application (in contrast to the
>applet) freezes immediately after typing the last letter of the command
>"pause".
>
>
that's a bug. Introduced in 11.3.10; fixed in Jmol 11.3.26.
>---- Test System ----------------
> Jmol: 11.3.25, application
> Java: 1.5.0_12
> OS : Linux, OpenSuSE 10.2
>---------------------------------
>
>Regards,
>Rolf
>
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--
Robert M. Hanson
Professor of Chemistry
St. Olaf College
Northfield, MN
http://www.stolaf.edu/people/hansonr
If nature does not answer first what we want,
it is better to take what answer we get.
-- Josiah Willard Gibbs, Lecture XXX, Monday, February 5, 1900
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