..oh, and just to clarify - again, from the documentation, I thought
that arrays use indices 1 - array length rather than 0 - (array length
- 1) ?

2009/6/16 N David Brown <[email protected]>:
> Why the change to the modulus? If you have simply i % colors.size, if
> size is 3 for example you get
>
> i = 1 -> modulus is 1
> i = 2 -> modulus is 2
> i = 3 -> modulus is 0 (which selects the last array member, according
> to the documentation)
> i = 4 -> modulus is 1
> ..etc.
>
> I didn't know I couldn't put expressions in math, thanks for pointing
> that out; saves some future headaches!
>
> Dave
>
>
> 2009/6/16 Robert Hanson <[email protected]>:
>> A few corrections there:
>>
>> the colors need quotes
>> the */i won't work -- can't mix math and select expressions that way --
>> should be model=i
>> the color line needs @{   }  surrounding the math so the processor knows to
>> treat it as a math expression.
>> Also, since the array is numbered 1 - 3 you would want, while modulus would
>> go 0 to 2. I would suggest:
>>
>>
>> var mycolors = ["red", "orange", "green"];
>> var ncolors = mycolors.size
>> var m = n; // 'n' is your model count here
>> for (var i = 1; i <= m; i = i + 1)
>> {
>>  select model=i
>>  color atoms @{mycolors[1 + (i - 1)% ncolors]};
>> }
>>
>> Ah, but the problem is "model" refers to the number the author has assigned
>> -- usually just "1" for a model in a file. If there are multiple files, then
>> each model is still probably just "model=1" -- at least if they are PDB
>> files. A better solution would be if we could just say:
>>
>> color atoms property modelindex
>>
>>
>> See Jmol 11.7.42
>> http://chemapps.stolaf.edu/jmol/docs/examples-11/Jmol-11.zip
>> and http://chemapps.stolaf.edu/jmol/docs/examples-11/new.htm
>>
>> ;)
>>
>>
>> Bob
>>
>> On Tue, Jun 16, 2009 at 12:46 PM, N David Brown <[email protected]>
>> wrote:
>>>
>>> I haven't tried after writing it, but this should work:
>>>
>>> var mycolors = [red, orange, green];
>>> var m = n + 1; // 'n' is your model count here
>>> for (var i = 1; i < m; i = i + 1)
>>> {
>>>  select */i;
>>>  color atoms mycolors[i % mycolors.size];
>>> }
>>>
>>> The 'i % mycolors.size' means that if you get to the end of your
>>> colors list, it'll start reusing them from the beginning.
>>>
>>> Note that you can specify colors in the form [r, g, b] as well, where
>>> 'r', 'g' and 'b' are values from 0 - 255.
>>>
>>> Best,
>>>
>>> Dave
>>>
>>>
>>> 2009/6/16 Marie-Christine Vallet <[email protected]>:
>>> > Hi,
>>> > I have a jmol window with n number of models and would like to color
>>> > each of my models with a different color without having to select each
>>> > model manually. I would like a script to do this automatically, is it
>>> > possible? Did I miss something in the mailing list that would answer
>>> > that question.
>>> > Thanks,
>>> > Marie
>>> >
>>> >
>>> > ------------------------------------------------------------------------------
>>> > Crystal Reports - New Free Runtime and 30 Day Trial
>>> > Check out the new simplified licensing option that enables unlimited
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>>> > Jmol-users mailing list
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>>> >
>>>
>>>
>>>
>>> --
>>>
>>> - N David Brown
>>>
>>>
>>> ------------------------------------------------------------------------------
>>> Crystal Reports - New Free Runtime and 30 Day Trial
>>> Check out the new simplified licensing option that enables unlimited
>>> royalty-free distribution of the report engine for externally facing
>>> server and web deployment.
>>> http://p.sf.net/sfu/businessobjects
>>> _______________________________________________
>>> Jmol-users mailing list
>>> [email protected]
>>> https://lists.sourceforge.net/lists/listinfo/jmol-users
>>
>>
>>
>> --
>> Robert M. Hanson
>> Professor of Chemistry
>> St. Olaf College
>> 1520 St. Olaf Ave.
>> Northfield, MN 55057
>> http://www.stolaf.edu/people/hansonr
>> phone: 507-786-3107
>>
>>
>> If nature does not answer first what we want,
>> it is better to take what answer we get.
>>
>> -- Josiah Willard Gibbs, Lecture XXX, Monday, February 5, 1900
>>
>
>
>
> --
>
> - N David Brown
>



-- 

- N David Brown

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