Not seeing that....
$ for(var i IN {selected}) {print i.label()}
H #1
H #2
H #3
H #4
C #5
C #6
C #7
C #8
S #9
$ for(var i IN {selected}) {show i}
i = ({0})
i = ({1})
i = ({2})
i = ({3})
i = ({4})
i = ({5})
i = ({6})
i = ({7})
i = ({8})
??
On Tue, Nov 27, 2012 at 11:47 AM, Rolf Huehne <[email protected]>wrote:
> for(var i IN {selected}) {print i.label()}
--
Robert M. Hanson
Larson-Anderson Professor of Chemistry
Chair, Chemistry Department
St. Olaf College
Northfield, MN
http://www.stolaf.edu/people/hansonr
If nature does not answer first what we want,
it is better to take what answer we get.
-- Josiah Willard Gibbs, Lecture XXX, Monday, February 5, 1900
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